Codxplore.com

Latest news: New android application Islamic Video has been released. its a free islamic video application for android smartphone. Download now!


4 Responses to “Installing and running the Zend Framework on XAMPP” 1) It is assume that XAMPP is installed on your windows system a)Must have the mod_rewrite extension installed and configured b)Must also ensure that Apache is configured to support .htaccess files. AllowOverride All 2) Zend is easy to get up and running on XAMPP. 3) Download latest (Zend Framework 1.11.6) Full from link >> http://framework.zend.com/download/latest a)Create folder named “ZendFramework” at C:\xampp\php path. b)Uncompress “Zend Framework 1.11.6.zip” then go to library >> Zend folder copy all the content and paste in above created ZendFramework folder at C:\xampp\php\ZendFramework 4) Then make sure to change the include path in \xampp\php\php.ini appe....

Views: 646


$(document).ready(function() { $("a[id=showOpenList]").addClass("selected"); oTable = $('#example').dataTable({ "bJQueryUI": true, "sPaginationType": "full_numbers" }); });

Views: 523


$path = "testUpload/";         $maxsize = 2000000;         $allowedType = array("image/jpg", "image/jpeg", "image/gif", "image/png");         foreach ($_FILES as $key => $value) {             //debugPrint($value);             if (!empty($value['name'])) {                 $target = $path . basename($value['name']);                 $extension = $value["type"];                 if ($value['size'] < $maxsize) {                     if (in_array($extension, $allowedType)) {                         if (move_uploaded_file($value['tmp_name'], $target)) {                             $filena....

Views: 543


$path = "upload/";         $target = $path . basename($_FILES['file']['name']);         $allowedType = array("image/jpg", "image/jpeg", "image/gif", "image/png");         $extension = $_FILES["file"]["type"];         if (in_array($extension, $allowedType)) {             if (move_uploaded_file($_FILES['file']['tmp_name'], $target)) {                 $data['image'] = basename($_FILES['file']['name']);             }         }

Views: 515

Subscribe Us


Follow Us